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11983412544113 is a prime number
BaseRepresentation
bin1010111001100001101100…
…0011000100001001110001
31120102121021121212001000102
42232120123003010021301
53032314012102402423
641253034223202145
72344526063656553
oct256303303041161
946377247761012
1011983412544113
113900155a7977a
121416570746355
1368c05301062a
142d6000a0b4d3
1515bab1a88c28
hexae61b0c4271

11983412544113 has 2 divisors, whose sum is σ = 11983412544114. Its totient is φ = 11983412544112.

The previous prime is 11983412544107. The next prime is 11983412544127. The reversal of 11983412544113 is 31144521438911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9023006684224 + 2960405859889 = 3003832^2 + 1720583^2 .

It is a cyclic number.

It is not a de Polignac number, because 11983412544113 - 214 = 11983412527729 is a prime.

It is not a weakly prime, because it can be changed into another prime (11983412544413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706272056 + 5991706272057.

It is an arithmetic number, because the mean of its divisors is an integer number (5991706272057).

Almost surely, 211983412544113 is an apocalyptic number.

It is an amenable number.

11983412544113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11983412544113 is an equidigital number, since it uses as much as digits as its factorization.

11983412544113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 414720, while the sum is 47.

The spelling of 11983412544113 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, five hundred forty-four thousand, one hundred thirteen".