Base | Representation |
---|---|
bin | 1010111001100001101100… |
… | …0011000100001001110001 |
3 | 1120102121021121212001000102 |
4 | 2232120123003010021301 |
5 | 3032314012102402423 |
6 | 41253034223202145 |
7 | 2344526063656553 |
oct | 256303303041161 |
9 | 46377247761012 |
10 | 11983412544113 |
11 | 3900155a7977a |
12 | 1416570746355 |
13 | 68c05301062a |
14 | 2d6000a0b4d3 |
15 | 15bab1a88c28 |
hex | ae61b0c4271 |
11983412544113 has 2 divisors, whose sum is σ = 11983412544114. Its totient is φ = 11983412544112.
The previous prime is 11983412544107. The next prime is 11983412544127. The reversal of 11983412544113 is 31144521438911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9023006684224 + 2960405859889 = 3003832^2 + 1720583^2 .
It is a cyclic number.
It is not a de Polignac number, because 11983412544113 - 214 = 11983412527729 is a prime.
It is not a weakly prime, because it can be changed into another prime (11983412544413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706272056 + 5991706272057.
It is an arithmetic number, because the mean of its divisors is an integer number (5991706272057).
Almost surely, 211983412544113 is an apocalyptic number.
It is an amenable number.
11983412544113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11983412544113 is an equidigital number, since it uses as much as digits as its factorization.
11983412544113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 414720, while the sum is 47.
The spelling of 11983412544113 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, five hundred forty-four thousand, one hundred thirteen".
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