Base | Representation |
---|---|
bin | 1010111001100001101100… |
… | …0011101100001011110101 |
3 | 1120102121021122011100221110 |
4 | 2232120123003230023311 |
5 | 3032314012123124320 |
6 | 41253034230505233 |
7 | 2344526065241610 |
oct | 256303303541365 |
9 | 46377248140843 |
10 | 11983412708085 |
11 | 3900156080995 |
12 | 1416570805219 |
13 | 68c05306a160 |
14 | 2d6000a51177 |
15 | 15bab1abc5e0 |
hex | ae61b0ec2f5 |
11983412708085 has 64 divisors (see below), whose sum is σ = 24411832865280. Its totient is φ = 4882366540800.
The previous prime is 11983412708041. The next prime is 11983412708107. The reversal of 11983412708085 is 58080721438911.
It is a happy number.
It is not a de Polignac number, because 11983412708085 - 29 = 11983412707573 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 151323466 + ... + 151402635.
It is an arithmetic number, because the mean of its divisors is an integer number (381434888520).
Almost surely, 211983412708085 is an apocalyptic number.
11983412708085 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11983412708085 is an abundant number, since it is smaller than the sum of its proper divisors (12428420157195).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11983412708085 is a wasteful number, since it uses less digits than its factorization.
11983412708085 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302726158.
The product of its (nonzero) digits is 3870720, while the sum is 57.
The spelling of 11983412708085 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, seven hundred eight thousand, eighty-five".
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