11983991952 has 20 divisors (see below), whose sum is σ = 30958646000. Its totient is φ = 3994663968.

The previous prime is 11983991939. The next prime is 11983992071. The reversal of 11983991952 is 25919938911.

It is a super-3 number, since 3×11983991952³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11983991892 and 11983991901.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124833202 + ... + 124833297.

It is an arithmetic number, because the mean of its divisors is an integer number (1547932300).

Almost surely, 2^11983991952 is an apocalyptic number.

11983991952 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11983991952 is an abundant number, since it is smaller than the sum of its proper divisors (18974654048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11983991952 is a wasteful number, since it uses less digits than its factorization.

11983991952 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249666510 (or 249666504 counting only the distinct ones).

The product of its digits is 1574640, while the sum is 57.

The spelling of 11983991952 in words is "eleven billion, nine hundred eighty-three million, nine hundred ninety-one thousand, nine hundred fifty-two".