Base | Representation |
---|---|
bin | 10110010100100110… |
… | …10011010100000111 |
3 | 1010221011222212121012 |
4 | 23022103103110013 |
5 | 144020400221241 |
6 | 5301054312435 |
7 | 602655152252 |
oct | 131223232407 |
9 | 33834885535 |
10 | 11983992071 |
11 | 509a718687 |
12 | 23a54b871b |
13 | 118ca4b48c |
14 | 819852099 |
15 | 4a215c6eb |
hex | 2ca4d3507 |
11983992071 has 2 divisors, whose sum is σ = 11983992072. Its totient is φ = 11983992070.
The previous prime is 11983991939. The next prime is 11983992077. The reversal of 11983992071 is 17029938911.
It is a strong prime.
It is an emirp because it is prime and its reverse (17029938911) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11983992071 - 226 = 11916883207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11983992077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991996035 + 5991996036.
It is an arithmetic number, because the mean of its divisors is an integer number (5991996036).
Almost surely, 211983992071 is an apocalyptic number.
11983992071 is a deficient number, since it is larger than the sum of its proper divisors (1).
11983992071 is an equidigital number, since it uses as much as digits as its factorization.
11983992071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 50.
The spelling of 11983992071 in words is "eleven billion, nine hundred eighty-three million, nine hundred ninety-two thousand, seventy-one".
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