1198404451 has 2 divisors, whose sum is σ = 1198404452. Its totient is φ = 1198404450.

The previous prime is 1198404379. The next prime is 1198404503. The reversal of 1198404451 is 1544048911.

It is a strong prime.

It is an emirp because it is prime and its reverse (1544048911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1198404451 - 2⁹ = 1198403939 is a prime.

It is a super-2 number, since 2×1198404451² = 2872346456353222802, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1198404451.

It is not a weakly prime, because it can be changed into another prime (1198444451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599202225 + 599202226.

It is an arithmetic number, because the mean of its divisors is an integer number (599202226).

Almost surely, 2^1198404451 is an apocalyptic number.

1198404451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1198404451 is an equidigital number, since it uses as much as digits as its factorization.

1198404451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 37.

The square root of 1198404451 is about 34617.9787249342. The cubic root of 1198404451 is about 1062.1873814485.

The spelling of 1198404451 in words is "one billion, one hundred ninety-eight million, four hundred four thousand, four hundred fifty-one".