1198404503 has 2 divisors, whose sum is σ = 1198404504. Its totient is φ = 1198404502.

The previous prime is 1198404451. The next prime is 1198404509. The reversal of 1198404503 is 3054048911.

It is a strong prime.

It is an emirp because it is prime and its reverse (3054048911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1198404503 - 2²⁴ = 1181627287 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1198404509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599202251 + 599202252.

It is an arithmetic number, because the mean of its divisors is an integer number (599202252).

Almost surely, 2^1198404503 is an apocalyptic number.

1198404503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1198404503 is an equidigital number, since it uses as much as digits as its factorization.

1198404503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 35.

The square root of 1198404503 is about 34617.9794759891. The cubic root of 1198404503 is about 1062.1873968116.

The spelling of 1198404503 in words is "one billion, one hundred ninety-eight million, four hundred four thousand, five hundred three".