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11984346293 is a prime number
BaseRepresentation
bin10110010100101001…
…01001110010110101
31010221012122212111112
423022110221302311
5144020443040133
65301110044405
7602661156053
oct131224516265
933835585445
1011984346293
11509a93a827
1223a5649705
13118cb4378a
148199051d3
154a21cc648
hex2ca529cb5

11984346293 has 2 divisors, whose sum is σ = 11984346294. Its totient is φ = 11984346292.

The previous prime is 11984346281. The next prime is 11984346421. The reversal of 11984346293 is 39264348911.

11984346293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11316278884 + 668067409 = 106378^2 + 25847^2 .

It is a cyclic number.

It is not a de Polignac number, because 11984346293 - 28 = 11984346037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11984346223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5992173146 + 5992173147.

It is an arithmetic number, because the mean of its divisors is an integer number (5992173147).

Almost surely, 211984346293 is an apocalyptic number.

It is an amenable number.

11984346293 is a deficient number, since it is larger than the sum of its proper divisors (1).

11984346293 is an equidigital number, since it uses as much as digits as its factorization.

11984346293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1119744, while the sum is 50.

The spelling of 11984346293 in words is "eleven billion, nine hundred eighty-four million, three hundred forty-six thousand, two hundred ninety-three".