Base | Representation |
---|---|
bin | 1110010010010… |
… | …11000011000001 |
3 | 22100111202111211 |
4 | 13021023003001 |
5 | 221140020212 |
6 | 15520410121 |
7 | 2653444333 |
oct | 711130301 |
9 | 270452454 |
10 | 119845057 |
11 | 61716402 |
12 | 34176941 |
13 | 1baa1547 |
14 | 11cb9453 |
15 | a7c49a7 |
hex | 724b0c1 |
119845057 has 2 divisors, whose sum is σ = 119845058. Its totient is φ = 119845056.
The previous prime is 119845043. The next prime is 119845067. The reversal of 119845057 is 750548911.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96118416 + 23726641 = 9804^2 + 4871^2 .
It is a cyclic number.
It is not a de Polignac number, because 119845057 - 215 = 119812289 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (119845067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59922528 + 59922529.
It is an arithmetic number, because the mean of its divisors is an integer number (59922529).
Almost surely, 2119845057 is an apocalyptic number.
It is an amenable number.
119845057 is a deficient number, since it is larger than the sum of its proper divisors (1).
119845057 is an equidigital number, since it uses as much as digits as its factorization.
119845057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 40.
The square root of 119845057 is about 10947.3767177347. The cubic root of 119845057 is about 493.0300332662.
The spelling of 119845057 in words is "one hundred nineteen million, eight hundred forty-five thousand, fifty-seven".
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