119849753 has 2 divisors, whose sum is σ = 119849754. Its totient is φ = 119849752.

The previous prime is 119849707. The next prime is 119849761. The reversal of 119849753 is 357948911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85895824 + 33953929 = 9268^2 + 5827^2 .

It is an emirp because it is prime and its reverse (357948911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119849753 - 2⁸ = 119849497 is a prime.

It is a super-2 number, since 2×119849753² = 28727926588322018, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 119849698 and 119849707.

It is not a weakly prime, because it can be changed into another prime (119849783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59924876 + 59924877.

It is an arithmetic number, because the mean of its divisors is an integer number (59924877).

Almost surely, 2^119849753 is an apocalyptic number.

It is an amenable number.

119849753 is a deficient number, since it is larger than the sum of its proper divisors (1).

119849753 is an equidigital number, since it uses as much as digits as its factorization.

119849753 is an evil number, because the sum of its binary digits is even.

The product of its digits is 272160, while the sum is 47.

The square root of 119849753 is about 10947.5911962404. The cubic root of 119849753 is about 493.0364727997.

The spelling of 119849753 in words is "one hundred nineteen million, eight hundred forty-nine thousand, seven hundred fifty-three".