Base | Representation |
---|---|
bin | 10110010101000110… |
… | …00101110011101101 |
3 | 1010221110210011012211 |
4 | 23022203011303231 |
5 | 144022430143203 |
6 | 5301323130421 |
7 | 603035301253 |
oct | 131243056355 |
9 | 33843704184 |
10 | 11988131053 |
11 | 50a1a95328 |
12 | 23a6973a11 |
13 | 119086a392 |
14 | 81a20c5d3 |
15 | 4a26c8c6d |
hex | 2ca8c5ced |
11988131053 has 2 divisors, whose sum is σ = 11988131054. Its totient is φ = 11988131052.
The previous prime is 11988130981. The next prime is 11988131059. The reversal of 11988131053 is 35013188911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10882036489 + 1106094564 = 104317^2 + 33258^2 .
It is a cyclic number.
It is not a de Polignac number, because 11988131053 - 229 = 11451260141 is a prime.
It is a super-2 number, since 2×119881310532 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11988130997 and 11988131015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11988131059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5994065526 + 5994065527.
It is an arithmetic number, because the mean of its divisors is an integer number (5994065527).
Almost surely, 211988131053 is an apocalyptic number.
It is an amenable number.
11988131053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11988131053 is an equidigital number, since it uses as much as digits as its factorization.
11988131053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 40.
The spelling of 11988131053 in words is "eleven billion, nine hundred eighty-eight million, one hundred thirty-one thousand, fifty-three".
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