Search a number
-
+
11988131053 is a prime number
BaseRepresentation
bin10110010101000110…
…00101110011101101
31010221110210011012211
423022203011303231
5144022430143203
65301323130421
7603035301253
oct131243056355
933843704184
1011988131053
1150a1a95328
1223a6973a11
13119086a392
1481a20c5d3
154a26c8c6d
hex2ca8c5ced

11988131053 has 2 divisors, whose sum is σ = 11988131054. Its totient is φ = 11988131052.

The previous prime is 11988130981. The next prime is 11988131059. The reversal of 11988131053 is 35013188911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10882036489 + 1106094564 = 104317^2 + 33258^2 .

It is a cyclic number.

It is not a de Polignac number, because 11988131053 - 229 = 11451260141 is a prime.

It is a super-2 number, since 2×119881310532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11988130997 and 11988131015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11988131059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5994065526 + 5994065527.

It is an arithmetic number, because the mean of its divisors is an integer number (5994065527).

Almost surely, 211988131053 is an apocalyptic number.

It is an amenable number.

11988131053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11988131053 is an equidigital number, since it uses as much as digits as its factorization.

11988131053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 40.

The spelling of 11988131053 in words is "eleven billion, nine hundred eighty-eight million, one hundred thirty-one thousand, fifty-three".