Base | Representation |
---|---|
bin | 10110010101011101… |
… | …00001000000011001 |
3 | 1010221200102022120022 |
4 | 23022232201000121 |
5 | 144024212013131 |
6 | 5301511240225 |
7 | 603102614066 |
oct | 131256410031 |
9 | 33850368508 |
10 | 11991126041 |
11 | 50a3750524 |
12 | 23a7979075 |
13 | 119137866b |
14 | 81a78bc6d |
15 | 4a2abb37b |
hex | 2caba1019 |
11991126041 has 2 divisors, whose sum is σ = 11991126042. Its totient is φ = 11991126040.
The previous prime is 11991126013. The next prime is 11991126047. The reversal of 11991126041 is 14062119911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11991126016 + 25 = 109504^2 + 5^2 .
It is a cyclic number.
It is not a de Polignac number, because 11991126041 - 26 = 11991125977 is a prime.
It is a super-2 number, since 2×119911260412 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11991125992 and 11991126010.
It is not a weakly prime, because it can be changed into another prime (11991126047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5995563020 + 5995563021.
It is an arithmetic number, because the mean of its divisors is an integer number (5995563021).
Almost surely, 211991126041 is an apocalyptic number.
It is an amenable number.
11991126041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11991126041 is an equidigital number, since it uses as much as digits as its factorization.
11991126041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 35.
The spelling of 11991126041 in words is "eleven billion, nine hundred ninety-one million, one hundred twenty-six thousand, forty-one".
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