Base | Representation |
---|---|
bin | 10110010101100001… |
… | …01111001010110101 |
3 | 1010221201111220022222 |
4 | 23022300233022311 |
5 | 144024334131331 |
6 | 5301531532125 |
7 | 603110560544 |
oct | 131260571265 |
9 | 33851456288 |
10 | 11991708341 |
11 | 50a4008a68 |
12 | 23a7bba045 |
13 | 1191520712 |
14 | 81a8a015b |
15 | 4a2b83b7b |
hex | 2cac2f2b5 |
11991708341 has 2 divisors, whose sum is σ = 11991708342. Its totient is φ = 11991708340.
The previous prime is 11991708299. The next prime is 11991708367. The reversal of 11991708341 is 14380719911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10884748900 + 1106959441 = 104330^2 + 33271^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11991708341 is a prime.
It is a super-3 number, since 3×119917083413 (a number of 31 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11991708292 and 11991708301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11996708341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5995854170 + 5995854171.
It is an arithmetic number, because the mean of its divisors is an integer number (5995854171).
Almost surely, 211991708341 is an apocalyptic number.
It is an amenable number.
11991708341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11991708341 is an equidigital number, since it uses as much as digits as its factorization.
11991708341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 44.
The spelling of 11991708341 in words is "eleven billion, nine hundred ninety-one million, seven hundred eight thousand, three hundred forty-one".
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