Base | Representation |
---|---|
bin | 10110010101101110… |
… | …00011011101000101 |
3 | 1010221211122000212112 |
4 | 23022313003131011 |
5 | 144030300124133 |
6 | 5302031230405 |
7 | 603130625441 |
oct | 131267033505 |
9 | 33854560775 |
10 | 11993364293 |
11 | 50a4a3a119 |
12 | 23a8678405 |
13 | 1191980381 |
14 | 81abb1821 |
15 | 4a2dae648 |
hex | 2cadc3745 |
11993364293 has 2 divisors, whose sum is σ = 11993364294. Its totient is φ = 11993364292.
The previous prime is 11993364287. The next prime is 11993364301. The reversal of 11993364293 is 39246339911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8697800644 + 3295563649 = 93262^2 + 57407^2 .
It is a cyclic number.
It is not a de Polignac number, because 11993364293 - 28 = 11993364037 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11993367293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996682146 + 5996682147.
It is an arithmetic number, because the mean of its divisors is an integer number (5996682147).
Almost surely, 211993364293 is an apocalyptic number.
It is an amenable number.
11993364293 is a deficient number, since it is larger than the sum of its proper divisors (1).
11993364293 is an equidigital number, since it uses as much as digits as its factorization.
11993364293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 944784, while the sum is 50.
The spelling of 11993364293 in words is "eleven billion, nine hundred ninety-three million, three hundred sixty-four thousand, two hundred ninety-three".
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