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119934103 is a prime number
BaseRepresentation
bin1110010011000…
…00110010010111
322100200021122211
413021200302113
5221200342403
615522334251
72654265052
oct711406227
9270607584
10119934103
11617772a3
12341ba387
131bb02c33
1411cdda99
15a7e106d
hex7260c97

119934103 has 2 divisors, whose sum is σ = 119934104. Its totient is φ = 119934102.

The previous prime is 119934091. The next prime is 119934107. The reversal of 119934103 is 301439911.

It is a strong prime.

It is an emirp because it is prime and its reverse (301439911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119934103 - 221 = 117836951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119934107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59967051 + 59967052.

It is an arithmetic number, because the mean of its divisors is an integer number (59967052).

Almost surely, 2119934103 is an apocalyptic number.

119934103 is a deficient number, since it is larger than the sum of its proper divisors (1).

119934103 is an equidigital number, since it uses as much as digits as its factorization.

119934103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 31.

The square root of 119934103 is about 10951.4429642856. The cubic root of 119934103 is about 493.1521116804.

The spelling of 119934103 in words is "one hundred nineteen million, nine hundred thirty-four thousand, one hundred three".