Base | Representation |
---|---|
bin | 10110010101101111… |
… | …10111010011010001 |
3 | 1010221212000211011212 |
4 | 23022313313103101 |
5 | 144030323423112 |
6 | 5302035545505 |
7 | 603132501536 |
oct | 131267672321 |
9 | 33855024155 |
10 | 11993576657 |
11 | 50a5074727 |
12 | 23a875b295 |
13 | 1191a25c2a |
14 | 81ac28d8d |
15 | 4a2e02522 |
hex | 2cadf74d1 |
11993576657 has 2 divisors, whose sum is σ = 11993576658. Its totient is φ = 11993576656.
The previous prime is 11993576633. The next prime is 11993576681. The reversal of 11993576657 is 75667539911.
It is a balanced prime because it is at equal distance from previous prime (11993576633) and next prime (11993576681).
It can be written as a sum of positive squares in only one way, i.e., 8112785041 + 3880791616 = 90071^2 + 62296^2 .
It is a cyclic number.
It is not a de Polignac number, because 11993576657 - 230 = 10919834833 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11993576596 and 11993576605.
It is not a weakly prime, because it can be changed into another prime (11993576957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996788328 + 5996788329.
It is an arithmetic number, because the mean of its divisors is an integer number (5996788329).
Almost surely, 211993576657 is an apocalyptic number.
It is an amenable number.
11993576657 is a deficient number, since it is larger than the sum of its proper divisors (1).
11993576657 is an equidigital number, since it uses as much as digits as its factorization.
11993576657 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10716300, while the sum is 59.
The spelling of 11993576657 in words is "eleven billion, nine hundred ninety-three million, five hundred seventy-six thousand, six hundred fifty-seven".
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