Base | Representation |
---|---|
bin | 10110010101110000… |
… | …11101011000100101 |
3 | 1010221212022202011012 |
4 | 23022320131120211 |
5 | 144030343421040 |
6 | 5302043152005 |
7 | 603134021366 |
oct | 131270353045 |
9 | 33855282135 |
10 | 11993732645 |
11 | 50a5170944 |
12 | 23a8815605 |
13 | 1191a7bc2b |
14 | 81ac69b6d |
15 | 4a2e33865 |
hex | 2cae1d625 |
11993732645 has 54 divisors (see below), whose sum is σ = 15889830642. Its totient is φ = 8688911616.
The previous prime is 11993732633. The next prime is 11993732671. The reversal of 11993732645 is 54623739911.
11993732645 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 4017277924 + 7976454721 = 63382^2 + 89311^2 .
It is not a de Polignac number, because 11993732645 - 24 = 11993732629 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11993732593 and 11993732602.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 179010902 + ... + 179010968.
It is an arithmetic number, because the mean of its divisors is an integer number (294256123).
Almost surely, 211993732645 is an apocalyptic number.
It is an amenable number.
11993732645 is a deficient number, since it is larger than the sum of its proper divisors (3896097997).
11993732645 is an frugal number, since it uses more digits than its factorization.
11993732645 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 259 (or 132 counting only the distinct ones).
The product of its digits is 1224720, while the sum is 50.
The spelling of 11993732645 in words is "eleven billion, nine hundred ninety-three million, seven hundred thirty-two thousand, six hundred forty-five".
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