11993849281 has 2 divisors, whose sum is σ = 11993849282. Its totient is φ = 11993849280.

The previous prime is 11993849249. The next prime is 11993849381. The reversal of 11993849281 is 18294839911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7925450625 + 4068398656 = 89025^2 + 63784^2 .

It is a cyclic number.

It is not a de Polignac number, because 11993849281 - 2⁵ = 11993849249 is a prime.

It is a super-2 number, since 2×11993849281² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11993849221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996924640 + 5996924641.

It is an arithmetic number, because the mean of its divisors is an integer number (5996924641).

Almost surely, 2^11993849281 is an apocalyptic number.

It is an amenable number.

11993849281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11993849281 is an equidigital number, since it uses as much as digits as its factorization.

11993849281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1119744, while the sum is 55.

The spelling of 11993849281 in words is "eleven billion, nine hundred ninety-three million, eight hundred forty-nine thousand, two hundred eighty-one".