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11993849381 is a prime number
BaseRepresentation
bin10110010101110001…
…11001111000100101
31010221212112200021202
423022320321320211
5144030411140011
65302045452245
7603135015623
oct131270717045
933855480252
1011993849381
1150a5240618
1223a8871085
131191ac00c7
1481ac9a513
154a2e5823b
hex2cae39e25

11993849381 has 2 divisors, whose sum is σ = 11993849382. Its totient is φ = 11993849380.

The previous prime is 11993849281. The next prime is 11993849383. The reversal of 11993849381 is 18394839911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8823596356 + 3170253025 = 93934^2 + 56305^2 .

It is a cyclic number.

It is not a de Polignac number, because 11993849381 - 210 = 11993848357 is a prime.

It is a super-2 number, since 2×119938493812 (a number of 21 digits) contains 22 as substring.

Together with 11993849383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11993849383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996924690 + 5996924691.

It is an arithmetic number, because the mean of its divisors is an integer number (5996924691).

Almost surely, 211993849381 is an apocalyptic number.

It is an amenable number.

11993849381 is a deficient number, since it is larger than the sum of its proper divisors (1).

11993849381 is an equidigital number, since it uses as much as digits as its factorization.

11993849381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1679616, while the sum is 56.

The spelling of 11993849381 in words is "eleven billion, nine hundred ninety-three million, eight hundred forty-nine thousand, three hundred eighty-one".