Base | Representation |
---|---|
bin | 110111110111001101… |
… | …1011101000001000101 |
3 | 102110122111222102011010 |
4 | 1233232123131001011 |
5 | 3431141324304031 |
6 | 131035535032433 |
7 | 11444553435642 |
oct | 1575633350105 |
9 | 373574872133 |
10 | 119964291141 |
11 | 46970795572 |
12 | 1b2bb96b719 |
13 | b40a993a76 |
14 | 5b406ccdc9 |
15 | 31c1ca0246 |
hex | 1bee6dd045 |
119964291141 has 4 divisors (see below), whose sum is σ = 159952388192. Its totient is φ = 79976194092.
The previous prime is 119964291137. The next prime is 119964291163. The reversal of 119964291141 is 141192469911.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 119964291141 - 22 = 119964291137 is a prime.
It is a super-2 number, since 2×1199642911412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (119964291101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19994048521 + ... + 19994048526.
It is an arithmetic number, because the mean of its divisors is an integer number (39988097048).
Almost surely, 2119964291141 is an apocalyptic number.
It is an amenable number.
119964291141 is a deficient number, since it is larger than the sum of its proper divisors (39988097051).
119964291141 is an equidigital number, since it uses as much as digits as its factorization.
119964291141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39988097050.
The product of its digits is 139968, while the sum is 48.
The spelling of 119964291141 in words is "one hundred nineteen billion, nine hundred sixty-four million, two hundred ninety-one thousand, one hundred forty-one".
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