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119987788873 is a prime number
BaseRepresentation
bin110111110111111010…
…1000101110001001001
3102110201011012012222111
41233233311011301021
53431213333220443
6131042134422321
711445260243311
oct1575765056111
9373634165874
10119987788873
1146982a84787
121b3078019a1
13b412800254
145b43888441
1531c3d9269d
hex1befd45c49

119987788873 has 2 divisors, whose sum is σ = 119987788874. Its totient is φ = 119987788872.

The previous prime is 119987788871. The next prime is 119987788891. The reversal of 119987788873 is 378887789911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61902932809 + 58084856064 = 248803^2 + 241008^2 .

It is an emirp because it is prime and its reverse (378887789911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119987788873 - 21 = 119987788871 is a prime.

It is a super-2 number, since 2×1199877888732 (a number of 23 digits) contains 22 as substring.

Together with 119987788871, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 119987788873.

It is not a weakly prime, because it can be changed into another prime (119987788871) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59993894436 + 59993894437.

It is an arithmetic number, because the mean of its divisors is an integer number (59993894437).

Almost surely, 2119987788873 is an apocalyptic number.

It is an amenable number.

119987788873 is a deficient number, since it is larger than the sum of its proper divisors (1).

119987788873 is an equidigital number, since it uses as much as digits as its factorization.

119987788873 is an evil number, because the sum of its binary digits is even.

The product of its digits is 341397504, while the sum is 76.

The spelling of 119987788873 in words is "one hundred nineteen billion, nine hundred eighty-seven million, seven hundred eighty-eight thousand, eight hundred seventy-three".