119994863 has 2 divisors, whose sum is σ = 119994864. Its totient is φ = 119994862.

The previous prime is 119994859. The next prime is 119994871. The reversal of 119994863 is 368499911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 119994863 - 2² = 119994859 is a prime.

It is a super-3 number, since 3×119994863³ (a number of 25 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119994803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59997431 + 59997432.

It is an arithmetic number, because the mean of its divisors is an integer number (59997432).

Almost surely, 2^119994863 is an apocalyptic number.

119994863 is a deficient number, since it is larger than the sum of its proper divisors (1).

119994863 is an equidigital number, since it uses as much as digits as its factorization.

119994863 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 419904, while the sum is 50.

The square root of 119994863 is about 10954.2166766958. The cubic root of 119994863 is about 493.2353764704.

The spelling of 119994863 in words is "one hundred nineteen million, nine hundred ninety-four thousand, eight hundred sixty-three".