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119994881041957 is a prime number
BaseRepresentation
bin11011010010001001111100…
…010000100110011000100101
3120201212101202120120000121211
4123102021330100212120211
5111211444004021320312
61103112515355511421
734163226004565215
oct3322117420463045
9521771676500554
10119994881041957
11352635a80a7279
121155b98aa58571
1351c5612a4a50c
14218bad7284245
15dd15200523a7
hex6d227c426625

119994881041957 has 2 divisors, whose sum is σ = 119994881041958. Its totient is φ = 119994881041956.

The previous prime is 119994881041829. The next prime is 119994881042027. The reversal of 119994881041957 is 759140188499911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114872222879716 + 5122658162241 = 10717846^2 + 2263329^2 .

It is a cyclic number.

It is not a de Polignac number, because 119994881041957 - 27 = 119994881041829 is a prime.

It is a super-3 number, since 3×1199948810419573 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119994881041157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59997440520978 + 59997440520979.

It is an arithmetic number, because the mean of its divisors is an integer number (59997440520979).

Almost surely, 2119994881041957 is an apocalyptic number.

It is an amenable number.

119994881041957 is a deficient number, since it is larger than the sum of its proper divisors (1).

119994881041957 is an equidigital number, since it uses as much as digits as its factorization.

119994881041957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 235146240, while the sum is 76.

The spelling of 119994881041957 in words is "one hundred nineteen trillion, nine hundred ninety-four billion, eight hundred eighty-one million, forty-one thousand, nine hundred fifty-seven".