Base | Representation |
---|---|
bin | 11011010010001101100111… |
… | …000000101010111011000001 |
3 | 120201212202221001111000211201 |
4 | 123102031213000222323001 |
5 | 111212030040243341001 |
6 | 1103114410250541201 |
7 | 34163425420203163 |
oct | 3322154700527301 |
9 | 521782831430751 |
10 | 119998819512001 |
11 | 352652392850a1 |
12 | 115606a9a37801 |
13 | 51c5abc9a7771 |
14 | 218bd8c37c933 |
15 | dd16a0bc1501 |
hex | 6d236702aec1 |
119998819512001 has 2 divisors, whose sum is σ = 119998819512002. Its totient is φ = 119998819512000.
The previous prime is 119998819511933. The next prime is 119998819512017. The reversal of 119998819512001 is 100215918899911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113300164505025 + 6698655006976 = 10644255^2 + 2588176^2 .
It is a cyclic number.
It is not a de Polignac number, because 119998819512001 - 27 = 119998819511873 is a prime.
It is not a weakly prime, because it can be changed into another prime (119998819512601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59999409756000 + 59999409756001.
It is an arithmetic number, because the mean of its divisors is an integer number (59999409756001).
Almost surely, 2119998819512001 is an apocalyptic number.
It is an amenable number.
119998819512001 is a deficient number, since it is larger than the sum of its proper divisors (1).
119998819512001 is an equidigital number, since it uses as much as digits as its factorization.
119998819512001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 64.
The spelling of 119998819512001 in words is "one hundred nineteen trillion, nine hundred ninety-eight billion, eight hundred nineteen million, five hundred twelve thousand, one".
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