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12000000983 is a prime number
BaseRepresentation
bin10110010110100000…
…10111101111010111
31010222022010012200212
423023100113233113
5144034000012413
65302425400035
7603241216415
oct131320275727
933868105625
1012000000983
1150a8762393
1223aa93901b
1311931650c9
1481ba1c2b5
154a3770ca8
hex2cb417bd7

12000000983 has 2 divisors, whose sum is σ = 12000000984. Its totient is φ = 12000000982.

The previous prime is 12000000949. The next prime is 12000001043. The reversal of 12000000983 is 38900000021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12000000983 - 226 = 11932892119 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000000923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000000491 + 6000000492.

It is an arithmetic number, because the mean of its divisors is an integer number (6000000492).

Almost surely, 212000000983 is an apocalyptic number.

12000000983 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000000983 is an equidigital number, since it uses as much as digits as its factorization.

12000000983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 12000000983 in words is "twelve billion, nine hundred eighty-three", and thus it is an aban number.