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1200002121112 = 23150000265139
BaseRepresentation
bin10001011101100101101…
…100110011110110011000
311020201102012200212121011
4101131211230303312120
5124130101020333422
62315135014023304
7152461112506024
oct21354554636630
94221365625534
101200002121112
11422a10a05783
1217469a347b34
138920cb7b2c2
144211a91b384
1521334ea9077
hex11765b33d98

1200002121112 has 8 divisors (see below), whose sum is σ = 2250003977100. Its totient is φ = 600001060552.

The previous prime is 1200002121107. The next prime is 1200002121119. The reversal of 1200002121112 is 2111212000021.

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-2 number, since 2×12000021211122 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1200002121092 and 1200002121101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200002121119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75000132562 + ... + 75000132577.

Almost surely, 21200002121112 is an apocalyptic number.

It is an amenable number.

1200002121112 is a deficient number, since it is larger than the sum of its proper divisors (1050001855988).

1200002121112 is a wasteful number, since it uses less digits than its factorization.

1200002121112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150000265145 (or 150000265141 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1200002121112 its reverse (2111212000021), we get a palindrome (3311214121133).

It can be divided in two parts, 12000021 and 21112, that multiplied together give a palindrome (253344443352).

The spelling of 1200002121112 in words is "one trillion, two hundred billion, two million, one hundred twenty-one thousand, one hundred twelve".

Divisors: 1 2 4 8 150000265139 300000530278 600001060556 1200002121112