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1200004132013 is a prime number
BaseRepresentation
bin10001011101100101110…
…100011110110010101101
311020201102100111001000222
4101131211310132302231
5124130102024211023
62315135125101125
7152461135552511
oct21354564366255
94221370431028
101200004132013
11422a12059585
1217469ab577a5
138921040369b
144211acc2141
1521335254cc8
hex11765d1ecad

1200004132013 has 2 divisors, whose sum is σ = 1200004132014. Its totient is φ = 1200004132012.

The previous prime is 1200004131973. The next prime is 1200004132057. The reversal of 1200004132013 is 3102314000021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 823777694884 + 376226437129 = 907622^2 + 613373^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200004132013 - 240 = 100492504237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200004131982 and 1200004132000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200004132513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600002066006 + 600002066007.

It is an arithmetic number, because the mean of its divisors is an integer number (600002066007).

Almost surely, 21200004132013 is an apocalyptic number.

It is an amenable number.

1200004132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200004132013 is an equidigital number, since it uses as much as digits as its factorization.

1200004132013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1200004132013 its reverse (3102314000021), we get a palindrome (4302318132034).

The spelling of 1200004132013 in words is "one trillion, two hundred billion, four million, one hundred thirty-two thousand, thirteen".