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120001122013103 is a prime number
BaseRepresentation
bin11011010010001111110000…
…010000000000111110101111
3120201212222212112001012120022
4123102033300100000332233
5111212044244213404403
61103115430541312355
734163536446142322
oct3322176020007657
9521788775035508
10120001122013103
113526620aa54271
1211561030b656bb
1351c6098a17156
14218c12a09c7b9
15dd1787dd8d38
hex6d23f0400faf

120001122013103 has 2 divisors, whose sum is σ = 120001122013104. Its totient is φ = 120001122013102.

The previous prime is 120001122013063. The next prime is 120001122013169. The reversal of 120001122013103 is 301310221100021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120001122013103 - 26 = 120001122013039 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120001122073103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000561006551 + 60000561006552.

It is an arithmetic number, because the mean of its divisors is an integer number (60000561006552).

Almost surely, 2120001122013103 is an apocalyptic number.

120001122013103 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001122013103 is an equidigital number, since it uses as much as digits as its factorization.

120001122013103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 120001122013103 its reverse (301310221100021), we get a palindrome (421311343113124).

The spelling of 120001122013103 in words is "one hundred twenty trillion, one billion, one hundred twenty-two million, thirteen thousand, one hundred three".