1200012099173 has 2 divisors, whose sum is σ = 1200012099174. Its totient is φ = 1200012099172.

The previous prime is 1200012099151. The next prime is 1200012099193. The reversal of 1200012099173 is 3719902100021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 858304043809 + 341708055364 = 926447^2 + 584558^2 .

It is an emirp because it is prime and its reverse (3719902100021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200012099173 - 2¹⁰ = 1200012098149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200012099193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600006049586 + 600006049587.

It is an arithmetic number, because the mean of its divisors is an integer number (600006049587).

Almost surely, 2^{1200012099173} is an apocalyptic number.

It is an amenable number.

1200012099173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200012099173 is an equidigital number, since it uses as much as digits as its factorization.

1200012099173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 35.

Adding to 1200012099173 its reverse (3719902100021), we get a palindrome (4919914199194).

The spelling of 1200012099173 in words is "one trillion, two hundred billion, twelve million, ninety-nine thousand, one hundred seventy-three".