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120001212000120 = 23351129091909091
BaseRepresentation
bin11011010010001111110101…
…100111010010011101111000
3120201220000002210101000112210
4123102033311213102131320
5111212044440233000440
61103115443514135120
734163541621052203
oct3322176547223570
9521800083330483
10120001212000120
1135266256826900
12115610571214a0
1351c60b15631c9
14218c13800493a
15dd1790c61a80
hex6d23f59d2778

120001212000120 has 192 divisors, whose sum is σ = 395750438536320. Its totient is φ = 29087970912000.

The previous prime is 120001212000113. The next prime is 120001212000127. The reversal of 120001212000120 is 21000212100021.

It is an interprime number because it is at equal distance from previous prime (120001212000113) and next prime (120001212000127).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 120001212000096 and 120001212000105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120001212000127) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 131546775 + ... + 132455865.

It is an arithmetic number, because the mean of its divisors is an integer number (2061200200710).

Almost surely, 2120001212000120 is an apocalyptic number.

120001212000120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120001212000120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (197875219268160).

120001212000120 is an abundant number, since it is smaller than the sum of its proper divisors (275749226536200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120001212000120 is a wasteful number, since it uses less digits than its factorization.

120001212000120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 918218 (or 918203 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 12.

Adding to 120001212000120 its reverse (21000212100021), we get a palindrome (141001424100141).

Subtracting from 120001212000120 its reverse (21000212100021), we obtain a palindrome (99000999900099).

The spelling of 120001212000120 in words is "one hundred twenty trillion, one billion, two hundred twelve million, one hundred twenty", and thus it is an aban number.