Base | Representation |
---|---|
bin | 11011010010001111110101… |
… | …100111110000000000010111 |
3 | 120201220000002210121011111221 |
4 | 123102033311213300000113 |
5 | 111212044440300333421 |
6 | 1103115443520511211 |
7 | 34163541622065016 |
oct | 3322176547600027 |
9 | 521800083534457 |
10 | 120001212121111 |
11 | 352662568a97a2 |
12 | 1156105717b507 |
13 | 51c60b15a62b9 |
14 | 218c138036a7d |
15 | dd1790c87841 |
hex | 6d23f59f0017 |
120001212121111 has 2 divisors, whose sum is σ = 120001212121112. Its totient is φ = 120001212121110.
The previous prime is 120001212121103. The next prime is 120001212121123. The reversal of 120001212121111 is 111121212100021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120001212121111 - 23 = 120001212121103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120001212121411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000606060555 + 60000606060556.
It is an arithmetic number, because the mean of its divisors is an integer number (60000606060556).
Almost surely, 2120001212121111 is an apocalyptic number.
120001212121111 is a deficient number, since it is larger than the sum of its proper divisors (1).
120001212121111 is an equidigital number, since it uses as much as digits as its factorization.
120001212121111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 16.
Adding to 120001212121111 its reverse (111121212100021), we get a palindrome (231122424221132).
The spelling of 120001212121111 in words is "one hundred twenty trillion, one billion, two hundred twelve million, one hundred twenty-one thousand, one hundred eleven".
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