Base | Representation |
---|---|
bin | 10110010110100001… |
… | …10101010011111111 |
3 | 1010222022100100212002 |
4 | 23023100311103333 |
5 | 144034012401421 |
6 | 5302432132515 |
7 | 603242232515 |
oct | 131320652377 |
9 | 33868310762 |
10 | 12000122111 |
11 | 50a883539a |
12 | 23aa99713b |
13 | 11931a8293 |
14 | 81ba504b5 |
15 | 4a3796b0b |
hex | 2cb4354ff |
12000122111 has 2 divisors, whose sum is σ = 12000122112. Its totient is φ = 12000122110.
The previous prime is 12000122089. The next prime is 12000122149. The reversal of 12000122111 is 11122100021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12000122111 is a prime.
It is a super-2 number, since 2×120001221112 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12000122092 and 12000122101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12000122171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000061055 + 6000061056.
It is an arithmetic number, because the mean of its divisors is an integer number (6000061056).
Almost surely, 212000122111 is an apocalyptic number.
12000122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000122111 is an equidigital number, since it uses as much as digits as its factorization.
12000122111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 12000122111 its reverse (11122100021), we get a palindrome (23122222132).
The spelling of 12000122111 in words is "twelve billion, one hundred twenty-two thousand, one hundred eleven".
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