12000123300014 has 4 divisors (see below), whose sum is σ = 18000184950024. Its totient is φ = 6000061650006.

The previous prime is 12000123299999. The next prime is 12000123300019. The reversal of 12000123300014 is 41000332100021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12000123299965 and 12000123300001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000123300019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000030825002 + ... + 3000030825005.

It is an arithmetic number, because the mean of its divisors is an integer number (4500046237506).

Almost surely, 2^{12000123300014} is an apocalyptic number.

12000123300014 is a deficient number, since it is larger than the sum of its proper divisors (6000061650010).

12000123300014 is an equidigital number, since it uses as much as digits as its factorization.

12000123300014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6000061650009.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12000123300014 its reverse (41000332100021), we get a palindrome (53000455400035).

The spelling of 12000123300014 in words is "twelve trillion, one hundred twenty-three million, three hundred thousand, fourteen".