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12000131121232 = 24750008195077
BaseRepresentation
bin1010111010011111111110…
…0011011000000001010000
31120111012102202210202022101
42232213333203120001100
53033102232031334412
641304441212250144
72345660302353112
oct256477743300120
946435382722271
1012000131121232
1139072551a2161
121419857770954
136907b890b807
142d6b491913b2
1515c23e6c1457
hexae9ff8d8050

12000131121232 has 10 divisors (see below), whose sum is σ = 23250254047418. Its totient is φ = 6000065560608.

The previous prime is 12000131121197. The next prime is 12000131121247. The reversal of 12000131121232 is 23212113100021.

12000131121232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 8723611187776 + 3276519933456 = 2953576^2 + 1810116^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 375004097523 + ... + 375004097554.

Almost surely, 212000131121232 is an apocalyptic number.

It is an amenable number.

12000131121232 is a deficient number, since it is larger than the sum of its proper divisors (11250122926186).

12000131121232 is an equidigital number, since it uses as much as digits as its factorization.

12000131121232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 750008195085 (or 750008195079 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12000131121232 its reverse (23212113100021), we get a palindrome (35212244221253).

The spelling of 12000131121232 in words is "twelve trillion, one hundred thirty-one million, one hundred twenty-one thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 750008195077 1500016390154 3000032780308 6000065560616 12000131121232