120001312000501 has 2 divisors, whose sum is σ = 120001312000502. Its totient is φ = 120001312000500.

The previous prime is 120001312000483. The next prime is 120001312000547. The reversal of 120001312000501 is 105000213100021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116256893498001 + 3744418502500 = 10782249^2 + 1935050^2 .

It is a cyclic number.

It is not a de Polignac number, because 120001312000501 - 2⁷ = 120001312000373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120001312000601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000656000250 + 60000656000251.

It is an arithmetic number, because the mean of its divisors is an integer number (60000656000251).

Almost surely, 2^{120001312000501} is an apocalyptic number.

It is an amenable number.

120001312000501 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001312000501 is an equidigital number, since it uses as much as digits as its factorization.

120001312000501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 120001312000501 its reverse (105000213100021), we get a palindrome (225001525100522).

The spelling of 120001312000501 in words is "one hundred twenty trillion, one billion, three hundred twelve million, five hundred one", and thus it is an aban number.