Base | Representation |
---|---|
bin | 10001011101100110010… |
… | …111111010111000001001 |
3 | 11020201102222222000121212 |
4 | 101131212113322320021 |
5 | 124130111414001324 |
6 | 2315140100142505 |
7 | 152461310534336 |
oct | 21354627727011 |
9 | 4221388860555 |
10 | 1200013422089 |
11 | 422a17324329 |
12 | 1746a2097a35 |
13 | 89212307081 |
14 | 4211c21d98d |
15 | 21335e8c70e |
hex | 117665fae09 |
1200013422089 has 2 divisors, whose sum is σ = 1200013422090. Its totient is φ = 1200013422088.
The previous prime is 1200013422031. The next prime is 1200013422143. The reversal of 1200013422089 is 9802243100021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 685694956489 + 514318465600 = 828067^2 + 717160^2 .
It is a cyclic number.
It is not a de Polignac number, because 1200013422089 - 28 = 1200013421833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1200013422389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600006711044 + 600006711045.
It is an arithmetic number, because the mean of its divisors is an integer number (600006711045).
Almost surely, 21200013422089 is an apocalyptic number.
It is an amenable number.
1200013422089 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200013422089 is an equidigital number, since it uses as much as digits as its factorization.
1200013422089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 1200013422089 in words is "one trillion, two hundred billion, thirteen million, four hundred twenty-two thousand, eighty-nine".
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