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12000211109974 = 213512474440421
BaseRepresentation
bin1010111010100000010001…
…0100100000100001010110
31120111012122100022121020101
42232220010110200201112
53033102413021004344
641304453150524314
72345662263301333
oct256500424404126
946435570277211
1012000211109974
11390729636595a
12141987a50669a
136907cc366a29
142d6b55a5398a
1515c2467219d4
hexaea04520856

12000211109974 has 8 divisors (see below), whose sum is σ = 18000334039968. Its totient is φ = 6000099763320.

The previous prime is 12000211109927. The next prime is 12000211109989. The reversal of 12000211109974 is 47990111200021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×120002111099743 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 482284 + ... + 4922704.

It is an arithmetic number, because the mean of its divisors is an integer number (2250041754996).

Almost surely, 212000211109974 is an apocalyptic number.

12000211109974 is a deficient number, since it is larger than the sum of its proper divisors (6000122929994).

12000211109974 is a wasteful number, since it uses less digits than its factorization.

12000211109974 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5791670.

The product of its (nonzero) digits is 9072, while the sum is 37.

Adding to 12000211109974 its reverse (47990111200021), we get a palindrome (59990322309995).

The spelling of 12000211109974 in words is "twelve trillion, two hundred eleven million, one hundred nine thousand, nine hundred seventy-four".

Divisors: 1 2 1351247 2702494 4440421 8880842 6000105554987 12000211109974