12000211485733 has 2 divisors, whose sum is σ = 12000211485734. Its totient is φ = 12000211485732.

The previous prime is 12000211485707. The next prime is 12000211485737. The reversal of 12000211485733 is 33758411200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9002268142884 + 2997943342849 = 3000378^2 + 1731457^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000211485733 - 2⁵ = 12000211485701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12000211485692 and 12000211485701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000211485737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000105742866 + 6000105742867.

It is an arithmetic number, because the mean of its divisors is an integer number (6000105742867).

Almost surely, 2^{12000211485733} is an apocalyptic number.

It is an amenable number.

12000211485733 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000211485733 is an equidigital number, since it uses as much as digits as its factorization.

12000211485733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 12000211485733 its reverse (33758411200021), we get a palindrome (45758622685754).

The spelling of 12000211485733 in words is "twelve trillion, two hundred eleven million, four hundred eighty-five thousand, seven hundred thirty-three".