Base | Representation |
---|---|
bin | 10001011101100111000… |
… | …000101111000010010101 |
3 | 11020201110202002121110002 |
4 | 101131213000233002111 |
5 | 124130122133341433 |
6 | 2315141121341045 |
7 | 152461500506051 |
oct | 21354700570225 |
9 | 4221422077402 |
10 | 1200024121493 |
11 | 422a22371a0a |
12 | 1746a5797785 |
13 | 892145b2092 |
14 | 4211d806c61 |
15 | 21336da29e8 |
hex | 1176702f095 |
1200024121493 has 2 divisors, whose sum is σ = 1200024121494. Its totient is φ = 1200024121492.
The previous prime is 1200024121259. The next prime is 1200024121547. The reversal of 1200024121493 is 3941214200021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1032585210244 + 167438911249 = 1016162^2 + 409193^2 .
It is a cyclic number.
It is not a de Polignac number, because 1200024121493 - 228 = 1199755686037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1200024126493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600012060746 + 600012060747.
It is an arithmetic number, because the mean of its divisors is an integer number (600012060747).
Almost surely, 21200024121493 is an apocalyptic number.
It is an amenable number.
1200024121493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200024121493 is an equidigital number, since it uses as much as digits as its factorization.
1200024121493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
The spelling of 1200024121493 in words is "one trillion, two hundred billion, twenty-four million, one hundred twenty-one thousand, four hundred ninety-three".
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