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1200033021023 is a prime number
BaseRepresentation
bin10001011101100111100…
…010101011110001011111
311020201111100211202022022
4101131213202223301133
5124130131423133043
62315142040210355
7152461636243154
oct21354742536137
94221440752268
101200033021023
11422a273a02a1
121746a87699bb
13892163a9a85
1442120a8222b
1521337a5e868
hex117678abc5f

1200033021023 has 2 divisors, whose sum is σ = 1200033021024. Its totient is φ = 1200033021022.

The previous prime is 1200033021017. The next prime is 1200033021133. The reversal of 1200033021023 is 3201203300021.

It is a weak prime.

It is an emirp because it is prime and its reverse (3201203300021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200033021023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200033020992 and 1200033021010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200033021923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600016510511 + 600016510512.

It is an arithmetic number, because the mean of its divisors is an integer number (600016510512).

Almost surely, 21200033021023 is an apocalyptic number.

1200033021023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200033021023 is an equidigital number, since it uses as much as digits as its factorization.

1200033021023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 1200033021023 its reverse (3201203300021), we get a palindrome (4401236321044).

The spelling of 1200033021023 in words is "one trillion, two hundred billion, thirty-three million, twenty-one thousand, twenty-three".