Base | Representation |
---|---|
bin | 10001011101100111111… |
… | …110100100111101001110 |
3 | 11020201111212121020122020 |
4 | 101131213332210331032 |
5 | 124130140311130014 |
6 | 2315142501031010 |
7 | 152462055346236 |
oct | 21354776447516 |
9 | 4221455536566 |
10 | 1200040333134 |
11 | 422a30534a65 |
12 | 1746ab0b5466 |
13 | 89217a6a076 |
14 | 42121a26cc6 |
15 | 213385061a9 |
hex | 11767fa4f4e |
1200040333134 has 24 divisors (see below), whose sum is σ = 2508969020712. Its totient is φ = 382621554480.
The previous prime is 1200040333091. The next prime is 1200040333171. The reversal of 1200040333134 is 4313330400021.
It is a super-2 number, since 2×12000403331342 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 189039097 + ... + 189045444.
It is an arithmetic number, because the mean of its divisors is an integer number (104540375863).
Almost surely, 21200040333134 is an apocalyptic number.
1200040333134 is an abundant number, since it is smaller than the sum of its proper divisors (1308928687578).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1200040333134 is a wasteful number, since it uses less digits than its factorization.
1200040333134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378084592 (or 378084569 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 1200040333134 its reverse (4313330400021), we get a palindrome (5513370733155).
The spelling of 1200040333134 in words is "one trillion, two hundred billion, forty million, three hundred thirty-three thousand, one hundred thirty-four".
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