1200099130 has 16 divisors (see below), whose sum is σ = 2161396224. Its totient is φ = 479769040.

The previous prime is 1200099101. The next prime is 1200099133. The reversal of 1200099130 is 319900021.

1200099130 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 1200099095 and 1200099104.

It is not an unprimeable number, because it can be changed into a prime (1200099133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14686 + ... + 51145.

It is an arithmetic number, because the mean of its divisors is an integer number (135087264).

Almost surely, 2^1200099130 is an apocalyptic number.

1200099130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1200099130 is a deficient number, since it is larger than the sum of its proper divisors (961297094).

1200099130 is a wasteful number, since it uses less digits than its factorization.

1200099130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67661.

The product of its (nonzero) digits is 486, while the sum is 25.

The square root of 1200099130 is about 34642.4469401340. The cubic root of 1200099130 is about 1062.6878298613.

Adding to 1200099130 its reverse (319900021), we get a palindrome (1519999151).

The spelling of 1200099130 in words is "one billion, two hundred million, ninety-nine thousand, one hundred thirty".