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12001001978213 is a prime number
BaseRepresentation
bin1010111010100011001101…
…1101011011100101100101
31120111021200110110212111122
42232220303131123211211
53033111023001300323
641305103441543325
72346021005462543
oct256506335334545
946437613425448
1012001001978213
113907661829976
121419a5b344b45
136908c71702c1
142d6bccac2d93
1515c290d92ec8
hexaea3375b965

12001001978213 has 2 divisors, whose sum is σ = 12001001978214. Its totient is φ = 12001001978212.

The previous prime is 12001001978183. The next prime is 12001001978219. The reversal of 12001001978213 is 31287910010021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9783145351204 + 2217856627009 = 3127802^2 + 1489247^2 .

It is a cyclic number.

It is not a de Polignac number, because 12001001978213 - 214 = 12001001961829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12001001978219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000500989106 + 6000500989107.

It is an arithmetic number, because the mean of its divisors is an integer number (6000500989107).

Almost surely, 212001001978213 is an apocalyptic number.

It is an amenable number.

12001001978213 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001001978213 is an equidigital number, since it uses as much as digits as its factorization.

12001001978213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 35.

Adding to 12001001978213 its reverse (31287910010021), we get a palindrome (43288911988234).

The spelling of 12001001978213 in words is "twelve trillion, one billion, one million, nine hundred seventy-eight thousand, two hundred thirteen".