Search a number
-
+
1200102002131 is a prime number
BaseRepresentation
bin10001011101101011101…
…001110100110111010011
311020201200011122100121011
4101131223221310313103
5124130302103032011
62315152542511351
7152463434464234
oct21355351646723
94221604570534
101200102002131
11422a6232587a
12174707895557
138922777c8b6
1442129cbb08b
152133db38621
hex1176ba74dd3

1200102002131 has 2 divisors, whose sum is σ = 1200102002132. Its totient is φ = 1200102002130.

The previous prime is 1200102002101. The next prime is 1200102002207. The reversal of 1200102002131 is 1312002010021.

It is a weak prime.

It is an emirp because it is prime and its reverse (1312002010021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200102002131 - 213 = 1200101993939 is a prime.

It is a super-2 number, since 2×12001020021312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200102002101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600051001065 + 600051001066.

It is an arithmetic number, because the mean of its divisors is an integer number (600051001066).

Almost surely, 21200102002131 is an apocalyptic number.

1200102002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200102002131 is an equidigital number, since it uses as much as digits as its factorization.

1200102002131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1200102002131 its reverse (1312002010021), we get a palindrome (2512104012152).

The spelling of 1200102002131 in words is "one trillion, two hundred billion, one hundred two million, two thousand, one hundred thirty-one".