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12001020300041 is a prime number
BaseRepresentation
bin1010111010100011010010…
…0011010100101100001001
31120111021201201221201022212
42232220310203110230021
53033111042144100131
641305105334354505
72346021320302133
oct256506443245411
946437651851285
1012001020300041
113907671103383
121419a654bba35
136908cabb6916
142d6bd12d2053
1515c2927b1a2b
hexaea348d4b09

12001020300041 has 2 divisors, whose sum is σ = 12001020300042. Its totient is φ = 12001020300040.

The previous prime is 12001020300023. The next prime is 12001020300043. The reversal of 12001020300041 is 14000302010021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11299816710400 + 701203589641 = 3361520^2 + 837379^2 .

It is a cyclic number.

It is not a de Polignac number, because 12001020300041 - 226 = 12000953191177 is a prime.

Together with 12001020300043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12001020299989 and 12001020300025.

It is not a weakly prime, because it can be changed into another prime (12001020300043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000510150020 + 6000510150021.

It is an arithmetic number, because the mean of its divisors is an integer number (6000510150021).

Almost surely, 212001020300041 is an apocalyptic number.

It is an amenable number.

12001020300041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001020300041 is an equidigital number, since it uses as much as digits as its factorization.

12001020300041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 12001020300041 its reverse (14000302010021), we get a palindrome (26001322310062).

The spelling of 12001020300041 in words is "twelve trillion, one billion, twenty million, three hundred thousand, forty-one".