Base | Representation |
---|---|
bin | 10001011101101011101… |
… | …010010100010101111111 |
3 | 11020201200011212220110201 |
4 | 101131223222110111333 |
5 | 124130302121143241 |
6 | 2315152545344331 |
7 | 152463435542164 |
oct | 21355352242577 |
9 | 4221604786421 |
10 | 1200102131071 |
11 | 422a62403738 |
12 | 1747079380a7 |
13 | 892277c64ac |
14 | 42129d1206b |
15 | 2133db61931 |
hex | 1176ba9457f |
1200102131071 has 2 divisors, whose sum is σ = 1200102131072. Its totient is φ = 1200102131070.
The previous prime is 1200102130999. The next prime is 1200102131077. The reversal of 1200102131071 is 1701312010021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1200102131071 - 27 = 1200102130943 is a prime.
It is a super-3 number, since 3×12001021310713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1200102131077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600051065535 + 600051065536.
It is an arithmetic number, because the mean of its divisors is an integer number (600051065536).
Almost surely, 21200102131071 is an apocalyptic number.
1200102131071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200102131071 is an equidigital number, since it uses as much as digits as its factorization.
1200102131071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 1200102131071 its reverse (1701312010021), we get a palindrome (2901414141092).
The spelling of 1200102131071 in words is "one trillion, two hundred billion, one hundred two million, one hundred thirty-one thousand, seventy-one".
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