1200110213133 has 24 divisors (see below), whose sum is σ = 1873778077080. Its totient is φ = 735783880320.

The previous prime is 1200110213119. The next prime is 1200110213147. The reversal of 1200110213133 is 3313120110021.

It is an interprime number because it is at equal distance from previous prime (1200110213119) and next prime (1200110213147).

It can be written as a sum of positive squares in 4 ways, for example, as 29358080964 + 1170752132169 = 171342^2 + 1082013^2 .

It is not a de Polignac number, because 1200110213133 - 2⁴ = 1200110213117 is a prime.

It is a super-2 number, since 2×1200110213133² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200110213153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19034238 + ... + 19097183.

It is an arithmetic number, because the mean of its divisors is an integer number (78074086545).

Almost surely, 2^{1200110213133} is an apocalyptic number.

1200110213133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1200110213133 is a deficient number, since it is larger than the sum of its proper divisors (673667863947).

1200110213133 is a wasteful number, since it uses less digits than its factorization.

1200110213133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38131709 (or 38131706 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1200110213133 its reverse (3313120110021), we get a palindrome (4513230323154).

The spelling of 1200110213133 in words is "one trillion, two hundred billion, one hundred ten million, two hundred thirteen thousand, one hundred thirty-three".