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12001110221053 is a prime number
BaseRepresentation
bin1010111010100011100111…
…1010010110000011111101
31120111021222000011011202201
42232220321322112003331
53033111233204033203
641305122305551501
72346023461515412
oct256507172260375
946437860134681
1012001110221053
113907707940368
121419a8b645591
1369091370b915
142d6bdd21c109
1515c29a624e1d
hexaea39e960fd

12001110221053 has 2 divisors, whose sum is σ = 12001110221054. Its totient is φ = 12001110221052.

The previous prime is 12001110221047. The next prime is 12001110221101. The reversal of 12001110221053 is 35012201110021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11903417717689 + 97692503364 = 3450133^2 + 312558^2 .

It is an emirp because it is prime and its reverse (35012201110021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12001110221053 - 229 = 12000573350141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12001110221053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12001110221453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000555110526 + 6000555110527.

It is an arithmetic number, because the mean of its divisors is an integer number (6000555110527).

Almost surely, 212001110221053 is an apocalyptic number.

It is an amenable number.

12001110221053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001110221053 is an equidigital number, since it uses as much as digits as its factorization.

12001110221053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 12001110221053 its reverse (35012201110021), we get a palindrome (47013311331074).

The spelling of 12001110221053 in words is "twelve trillion, one billion, one hundred ten million, two hundred twenty-one thousand, fifty-three".