Base | Representation |
---|---|
bin | 11011010010011001000100… |
… | …010010111100000100010111 |
3 | 120201220221200102210011220222 |
4 | 123102121010102330010113 |
5 | 111212230234213001101 |
6 | 1103124203123544555 |
7 | 34164342323501444 |
oct | 3322310422740427 |
9 | 521827612704828 |
10 | 120011122000151 |
11 | 3526a48175a578 |
12 | 11562b61b2b15b |
13 | 51c70006cb755 |
14 | 218c7d821a9cb |
15 | dd1b70c9301b |
hex | 6d26444bc117 |
120011122000151 has 2 divisors, whose sum is σ = 120011122000152. Its totient is φ = 120011122000150.
The previous prime is 120011122000093. The next prime is 120011122000157. The reversal of 120011122000151 is 151000221110021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120011122000151 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120011122000157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005561000075 + 60005561000076.
It is an arithmetic number, because the mean of its divisors is an integer number (60005561000076).
Almost surely, 2120011122000151 is an apocalyptic number.
120011122000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
120011122000151 is an equidigital number, since it uses as much as digits as its factorization.
120011122000151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 120011122000151 its reverse (151000221110021), we get a palindrome (271011343110172).
The spelling of 120011122000151 in words is "one hundred twenty trillion, eleven billion, one hundred twenty-two million, one hundred fifty-one", and thus it is an aban number.
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