1200112313333 has 4 divisors (see below), whose sum is σ = 1225646617920. Its totient is φ = 1174578008748.

The previous prime is 1200112313291. The next prime is 1200112313339. The reversal of 1200112313333 is 3333132110021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200112313333 - 2¹² = 1200112309237 is a prime.

It is a super-2 number, since 2×1200112313333² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200112313299 and 1200112313308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200112313339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12767152223 + ... + 12767152316.

It is an arithmetic number, because the mean of its divisors is an integer number (306411654480).

Almost surely, 2^{1200112313333} is an apocalyptic number.

It is an amenable number.

1200112313333 is a deficient number, since it is larger than the sum of its proper divisors (25534304587).

1200112313333 is an equidigital number, since it uses as much as digits as its factorization.

1200112313333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25534304586.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1200112313333 its reverse (3333132110021), we get a palindrome (4533244423354).

The spelling of 1200112313333 in words is "one trillion, two hundred billion, one hundred twelve million, three hundred thirteen thousand, three hundred thirty-three".