Base | Representation |
---|---|
bin | 110111111000100111… |
… | …0111010001100000111 |
3 | 102110202210111110101022 |
4 | 1233301032322030013 |
5 | 3431240400200112 |
6 | 131044335221355 |
7 | 11445664340216 |
oct | 1576116721407 |
9 | 373683443338 |
10 | 120011334407 |
11 | 469952a68a8 |
12 | 1b31367785b |
13 | b417655413 |
14 | 5b46a5707d |
15 | 31c5e93d72 |
hex | 1bf13ba307 |
120011334407 has 2 divisors, whose sum is σ = 120011334408. Its totient is φ = 120011334406.
The previous prime is 120011334389. The next prime is 120011334413. The reversal of 120011334407 is 704433110021.
It is a strong prime.
It is an emirp because it is prime and its reverse (704433110021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120011334407 is a prime.
It is a super-2 number, since 2×1200113344072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120011334307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005667203 + 60005667204.
It is an arithmetic number, because the mean of its divisors is an integer number (60005667204).
Almost surely, 2120011334407 is an apocalyptic number.
120011334407 is a deficient number, since it is larger than the sum of its proper divisors (1).
120011334407 is an equidigital number, since it uses as much as digits as its factorization.
120011334407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 120011334407 its reverse (704433110021), we get a palindrome (824444444428).
The spelling of 120011334407 in words is "one hundred twenty billion, eleven million, three hundred thirty-four thousand, four hundred seven".
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